Write the general conic form equation for a circle with center (3, -1) and radius of 5. x 2 + y 2 - 15 = 0 x 2 - 6x + y 2 + 2y - 15 = 0 x 2 - 6x + y 2 + 2y + 5 = 0
we know that the equation of a circle in standard form is (x-h)²+(y-k)²=r² (h,k) is the center----------> (3,-1) r is the radius--------> r=5 units (x-3)²+(y+1)²=25------> x²-6x+9+y²+2y+1=25---> x²-6x+y²+2y-15=0
