Respuesta :
Use the equation for the area of a triangle:
[tex]A = \frac{1}{2} hb[/tex]
where A = area, h = height of the triangle, and b = base of the triangle.
You know that h=18m and A=99[tex]m^{2} [/tex]. Plug those values into the equation and solve for b, the base.
[tex]A = \frac{1}{2} hb \\ 99 = \frac{1}{2} (18)b \\ 99=9b\\ b=11[/tex]
The base is 11m long.
[tex]A = \frac{1}{2} hb[/tex]
where A = area, h = height of the triangle, and b = base of the triangle.
You know that h=18m and A=99[tex]m^{2} [/tex]. Plug those values into the equation and solve for b, the base.
[tex]A = \frac{1}{2} hb \\ 99 = \frac{1}{2} (18)b \\ 99=9b\\ b=11[/tex]
The base is 11m long.
use the area formula and solve for height.
Area of triangle = 1/2(b)(h)
99 = 1/2(b)(18)
99 = 9b
11 = b
Hope this helps :)
Area of triangle = 1/2(b)(h)
99 = 1/2(b)(18)
99 = 9b
11 = b
Hope this helps :)