The required volume of H₂SO₄ which is needed to react completely with LiOH is 16 mL.
In this question Volume of the solution will be calculated as:
M₁V₁ = M₂V₂, where
M₁ = molarity of LiOH = 0.4 M
V₁ = volume of LiOH = 20 mL
M₂ = molarity of H₂SO₄ = 0.5 M
V₂ = volume of H₂SO₄ = to find?
On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.4)(20) / (0.5) = 16 mL
Hence, the required volume is 16mL.
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