Answer:
D. 2 plus or minus square root of 2 end root over 2
Step-by-step explanation:
Given equation,
[tex]2x^2 - 8x = -7[/tex]
[tex]\implies 2x^2 - 8x + 7=0[/tex]
By the quadratic formula,
[tex]x=\frac{-(-8)\pm \sqrt{(-8)^2 -4\times 2\times 7}}{2\times 2}[/tex]
[tex]x=\frac{8\pm \sqrt{64 - 56}}{4}[/tex]
[tex]x=\frac{8\pm \sqrt{8}}{4}[/tex]
[tex]x=\frac{8\pm 2\sqrt{2}}{4}[/tex]
[tex]x=2\pm \frac{\sqrt{2}}{2}[/tex]
= 2 plus or minus square root of 2 end root over 2
OPTION D Is correct.
