Succinic acid is a diprotic acid with molar mass of 118 g/mol. calculate the mass of the acid required to neutralize 25.0 ml of a 0.100 m naoh solution.
Because it is diprotic acid, we can write like R(COOH)2 ( it can be written as H2A also) R(COOH)2+2NaOH ----> R(COONa)2+2H2O
25.0 ml of a 0.100 m NaOH solution 25.0 ml=0.0250 L solution Of NaOH 0.100 m NaOH=0.100 mol/L 0.0250 L *0.100 mol/L=0.00250 mol NaOH 0.00250 mol NaOH*1mol R(COOH)2/2 mol NaOH=0.00125 mol acid 0.00125 mol R(COOH)2*118g R(COOH)2/1mol R(COOH)2 = 0.148 g acid
