blessedmom1
contestada

PLEASE HELP!!!
Two pools are being filled with water. To start, the first pool contains 658 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 18.25 liters per minute. Water is being added to the second pool at a rate of 41.75 liters per minute.

After how many minutes will the two pools have the same amount of water?
How much water will be in each pool when they have the same amount?

Respuesta :

dpokharnaotzjgn
To solve this, make an equation:

658 + 18.25x = 0 + 41.75x

Then solve for x (simple algebra)

Minutes: 28 minutes
Amount of water: 1169 liters
musiclover10045
658 + 18.25m = 41.75m

658 = 23.5m

m = 658 / 23.5
m = 28 minutes they will have the same amount of water

18.25 x 28 = 511 + 658 = 1169

41.75 x 28 = 1169
 they will have 1169 liters each


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