Answer: The final temperature of the gas is 429.13 K.
Explanation:
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that the volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] = Initial volume and temperature of the gas
[tex]V_2\text{ and }T_2[/tex] = Final volume and temperature of the gas
We are given:
[tex]V_1=3.45L\\T_1=282K\\V_2=5.25L\\T_2=?K[/tex]
Putting values in above equation, we get:
[tex]\frac{3.45L}{282K}=\frac{5.25L}{T_2}\\\\T_2=429.13K[/tex]
Hence, the final temperature of the gas is 429.13 K.
The temperature of a gas when it is expanded to 5.25 L is 429.13 K. Gas is one of the states of matter, the atoms of gases are far away from each other and randomly move in space.
Temperature is the hotness or coldness of a body.
By the Charles law:
[tex]\dfrac{V_1}{T_1 } =\dfrac{V_2}{T_2}[/tex]
V1 and T1 are the initial volume and temperature respectively
V2 and T2 are the final volume and temperature respectively
Given that, V1 = 3.45L
V2 = 5.25 L
T1 = 282 K
To find the T2
Putting the values on the equation
[tex]\rm \dfrac{3.45}{282 } =\dfrac{5.25}{T_2} = 429.13 K\\\\\\T_2 = 429.13 K.[/tex]
Thus, the temperature of a gas when it is expanded to 5.25 L is 429.13 K.
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