Determine the discriminant for the quadratic equation –3 = x2 + 4x + 1. Based on the discriminant value, how many real number solutions does the equation have?
x^2 + 4x + 4 = 0 d = b^2 - 4ac, where a = 1, b = 4 and c = 4 d = 4^2 - 4 x 1 x 4 d = 16 - 16 = 0 Since d = 0, there is one real solution to the equation hope it helps
