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A bowl contains 10 red balls and 10 blue balls. a woman selects the balls at random without looking at them.
a.how many balls must she select to be sure of having at least three balls of the same color?
b.how many balls must she select to be sure of having at least three blue balls?

Respuesta :

musiclover10045
A,  3 red and 2 blue , or 3 blue and 2 red = 3+2 = 5

B. 5 ( from above) x 3 (blue) = 15 - 2( red) = 13
dsdrajlin

Answer:

a. 5

b. 13

Step-by-step explanation:

A bowl contains 10 red balls and 10 blue balls. a woman selects the balls at random without looking at them.

a. How many balls must she select to be sure of having at least three balls of the same color?

If she took 3 balls, there could be of the same color. However, she could not be sure of it. If she took 4 balls, she could have 2 red and 2 blue balls. Then, 5 is the minimum number of balls she could take to be sure that there are at least 3 of the same color.

b. How many balls must she select to be sure of having at least three blue balls?

If she took 12 balls, she could have 10 red balls and 2 blue balls. So, to be sure of having at least 3 blue balls, she should take 13 balls.

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