Respuesta :
The volume formula for a pyramid is:
V = ah[tex] \dfrac{1}{3} [/tex]
Where a = area of the base and h = height
Now, just plug in the numbers from this formula:
2592276 = a(146.5)[tex] \frac{1}{3} [/tex]
Now, first of all, to find the length of one side of the base, we need to find the area. What you do now is distribution
[tex]2592276 = a(146.5) \dfrac{1}{3}[/tex]
[tex]3 \times 2592276 = a(146.5) \dfrac{1}{3} \times 3[/tex]
[tex]7776828 = a(146.5)[/tex]
[tex] \dfrac{7776828 }{146.5} = \dfrac{a(146.5)}{146.5} [/tex]
[tex]53084.15017 = a[/tex]
The area is 53084.15017m². Now, because the base is a square (because it is a pyramid), plug this in the area formula:
L = length of side
[tex]53084.15017 = L^2[/tex]
Square root both sides, and you get the length of each side of the base as 230.399999999m
Round it to the nearest meter, and it is 230m
V = ah[tex] \dfrac{1}{3} [/tex]
Where a = area of the base and h = height
Now, just plug in the numbers from this formula:
2592276 = a(146.5)[tex] \frac{1}{3} [/tex]
Now, first of all, to find the length of one side of the base, we need to find the area. What you do now is distribution
[tex]2592276 = a(146.5) \dfrac{1}{3}[/tex]
[tex]3 \times 2592276 = a(146.5) \dfrac{1}{3} \times 3[/tex]
[tex]7776828 = a(146.5)[/tex]
[tex] \dfrac{7776828 }{146.5} = \dfrac{a(146.5)}{146.5} [/tex]
[tex]53084.15017 = a[/tex]
The area is 53084.15017m². Now, because the base is a square (because it is a pyramid), plug this in the area formula:
L = length of side
[tex]53084.15017 = L^2[/tex]
Square root both sides, and you get the length of each side of the base as 230.399999999m
Round it to the nearest meter, and it is 230m
Length of one side of the base of the regular pyramid with square base is equals to 230 meter.
What is regular pyramid with square base?
" Regular pyramid with square base is a three dimensional geometric shape which has square shape base and all the four sides of square have a triangle which are joined to a vertex."
Formula used
Volume of a pyramid with square base = [tex]\frac{1}{3} (Area of the base)^{2} height[/tex]
Area of the base = (side)²
According to the question,
Let length of side of the base = a
Height = 146.5 meters
Volume of a pyramid = 2,592,276 cubic meters
⇒2,592,276 = [tex]\frac{1}{3} a^{2} (146.5)[/tex]
⇒ a² = (2,592,276 × 3) / 146.5
⇒ a² =53084.15
⇒ a = 230.39
⇒ a = 230 meter ( nearest meter)
Hence, length of one side of the base of the regular pyramid with square base is equals to 230 meter.
Learn more about regular pyramid with square base here
https://brainly.com/question/20361014
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