Respuesta :

The roots would be 15 

Answer:

The roots of the equation is: [tex]x=\pm i\frac{\sqrt{7}}{7}[/tex]

Step-by-step explanation:

Consider the provided equation.

[tex]7x^2+1=0[/tex]

Subtract 1 from both the sides.

[tex]7x^2+1-1=-1[/tex]

[tex]7x^2=-1[/tex]

Isolate the variable by dividing both the side by 7.

[tex]\frac{7x^2}{7}=\frac{-1}{7}[/tex]

[tex]x^2=\frac{-1}{7}[/tex]

Take the square root:

[tex]x=\pm \sqrt{\frac{-1}{7}}[/tex]

[tex]x=\pm \frac{1}{\sqrt{7}}i[/tex]

Now we multiply the numerator and the denominator by √7:

[tex]x=\pm \frac{1}{\sqrt{7}}\times \frac{\sqrt{7}}{\sqrt{7}}i[/tex]

[tex]x=\pm \frac{\sqrt{7}}{7}i[/tex]

[tex]x=\pm i\frac{\sqrt{7}}{7}[/tex]

Hence, the roots of the equation is: [tex]x=\pm i\frac{\sqrt{7}}{7}[/tex]