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Part A (7 points): How many grams of iron (Fe) will be produced if you start with 3.65 liters of carbon monoxide gas (CO) at STP?

Part B (3 points): Jacob performed the above experiment in his chemistry class, and collected 4.23 grams of iron. What is the percent yield?

Fe2O3 + 3 CO --> 2 Fe + 3 CO2

Respuesta :

what is this? i still haven't gotten this bonus question.

Chlidonias

The given balanced chemical equation is,

[tex] Fe_{2}O_{3} + 3CO -->2 Fe (s) + 3CO_{2}(g) [/tex]

Part A:

Converting 3.65 L CO to moles:

[tex] 3.65 L * \frac{1 mol}{22.4 L} = 0.163 mol CO [/tex]

Moles of Fe that will be produced from 0.163 mol CO:

[tex] 0.163 mol CO * \frac{2 mol Fe}{3 mol CO} = 0.1086 mol Fe [/tex]

Mass of Fe = [tex] 0.1086 mol Fe * \frac{55.85 g}{1 mol} = 6.07 g Fe [/tex]

Part B: Actual yield of Fe = 4.23 g Fe.

Theoretical yield = 6.07 g Fe

Percentage yield = [tex] \frac{Actual yield (g)}{Theoretical yield (g)}*100 [/tex]

=69.7 %

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