Answer:
Jillian is not correct
Jillian has summed up the possible number of codes for each digit instead of multiplying it
Step-by-step explanation:
The lock has a code that consists of 3 number
It is given that the number in the lock code can be used between [tex]0[/tex] to [tex]39[/tex]
Thus, out of total [tex]40[/tex] set of numbers (i.e [tex]0-39[/tex]), the numbers can be repeated.
This means for all three code numbers the opportunity of choosing a number is same i.e. between [tex]0-39[/tex]
Now, the first digit of the code can be any number between [tex]0-39[/tex]
Like wise the second and third digit of the code can be any number between [tex]0-39[/tex]
Thus. the possible number of codes with repetition allowed are
[tex]40 * 40* 40\\64000[/tex]
Hence, Jillian is not correct
Jillian has summed up the possible number of codes for each digit instead of multiplying it
Answer:
No, Jillian is not correct. According to the fundamental counting principle, the total number of possible codes would be (40)(40)(40) = 64,000. Jillian multiplied by 3 instead of multiplying the number of possibilities for each digit.
Step-by-step explanation:
