Respuesta :
Answer : The balanced chemical reaction will be,
[tex]2HNO_3(aq)+K_2SO_3(aq)\rightarrow K_2SO_4(aq)+H_2O(l)+2NO_2(g)[/tex]
Explanation :
Balanced chemical equation : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
When the nitric acid react with potassium sulfite to give potassium sulfate, water and nitrogen dioxide.
Thus, the balanced chemical reaction will be,
[tex]2HNO_3(aq)+K_2SO_3(aq)\rightarrow K_2SO_4(aq)+H_2O(l)+2NO_2(g)[/tex]
The balanced chemical equation is as follows:
[tex]\boxed{{\text{2HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {{\text{K}}_2}{\text{S}}{{\text{O}}_3}\left( {aq} \right) \to {{\text{K}}_2}{\text{S}}{{\text{O}}_4}\left( {aq} \right) + 2{\text{N}}{{\text{O}}_{\text{2}}}\left( g \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( l \right)}[/tex]
The phase of [tex]{{\mathbf{K}}_{\mathbf{2}}}{\mathbf{S}}{{\mathbf{O}}_{\mathbf{4}}}[/tex] is [tex]\boxed{{\mathbf{aqueous}}}[/tex], [tex]{\mathbf{N}}{{\mathbf{O}}_{\mathbf{2}}}[/tex] is [tex]\boxed{{\mathbf{gas}}}[/tex] and [tex]{{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}[/tex] is [tex]\boxed{{\mathbf{liquid}}}[/tex].
Further Explanation:
The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.
The steps to balance a chemical reaction are as follows:
Step 1: Complete the reaction and write the unbalanced symbol equation.
In the given reaction, [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex] reacts with [tex]{{\text{K}}_2}{\text{S}}{{\text{O}}_3}[/tex] to form [tex]{{\text{K}}_2}{\text{S}}{{\text{O}}_4}[/tex], [tex]{\text{N}}{{\text{O}}_{\text{2}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex]. The physical state of [tex]{{\text{K}}_2}{\text{S}}{{\text{O}}_4}[/tex] is aqueous, [tex]{\text{N}}{{\text{O}}_{\text{2}}}[/tex] is gas and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] is liquid. The unbalanced chemical equation is as follows:
[tex]{\text{HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {{\text{K}}_2}{\text{S}}{{\text{O}}_3}\left( {aq} \right) \to {{\text{K}}_2}{\text{S}}{{\text{O}}_4}\left( {aq} \right) + {\text{N}}{{\text{O}}_{\text{2}}}\left( g \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( l \right)[/tex]
Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.(Refer table in the attached image)
- On the reactant side,
Number of hydrogen atoms is 1.
Number of nitrogen atoms is 1.
Number of oxygen atoms is 6.
Number of potassium atoms is 2.
Number of sulfur atoms is 1.
- On the product side,
Number of hydrogen atoms is 1.
Number of nitrogen atoms is 1.
Number of oxygen atoms is 6.
Number of potassium atoms is 2.
Number of sulfur atoms is 1.
Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. The other elements except oxygen and hydrogen are balanced.
Step 4: After this we balance the number of atoms of oxygen followed by hydrogen atoms. To balance the number of atoms of oxygen and hydrogen, we have to multiply [tex]{\text{HN}}{{\text{O}}_{\text{3}}}[/tex] by 2, [tex]{\text{N}}{{\text{O}}_{\text{2}}}[/tex] by 2. The chemical equation is as follows:
[tex]{\text{2HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {{\text{K}}_2}{\text{S}}{{\text{O}}_3}\left( {aq} \right) \to {{\text{K}}_2}{\text{S}}{{\text{O}}_4}\left( {aq} \right) + 2{\text{N}}{{\text{O}}_{\text{2}}}\left( g \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( l \right)[/tex]
Step 5: Finally, we check the number of atoms of each element on both the sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:
[tex]{\text{HN}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {{\text{K}}_2}{\text{S}}{{\text{O}}_3}\left( {aq} \right) \to {{\text{K}}_2}{\text{S}}{{\text{O}}_4}\left( {aq} \right) + {\text{N}}{{\text{O}}_{\text{2}}}\left( g \right) + {{\text{H}}_{\text{2}}}{\text{O}}\left( l \right)[/tex]
Learn more:
1. Balanced chemical equation https://brainly.com/question/1405182
2. How to calculate moles of the base in given volume https://brainly.com/question/4283309
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Chemical reaction and equation
Keywords: Balancing, HNO3, K2SO4, K2SO3, NO2, H2O, phases, physical state, solid, liquid, gas, aqueous, law of conservation of mass.
