Answer: 2.25 × 10⁴ N/C
Explanation:
The magnitude of the electric field strength is given by:
[tex]E = \frac{F}{q}[/tex]
where, F is the electrostatic force and q is the charge.
It is given that the magnitude of the force acting on an electron kept between the plates is: F = 3.60 ×10⁻¹⁵ N
Charge of the electron, q = 1.6 × 10⁻¹⁹ C
Thus, E = (3.60 ×10⁻¹⁵ N)÷(1.6 × 10⁻¹⁹ C) = 2.25 × 10⁴ N/C.
Thus, the electric field strength between the plates is 2.25 × 10⁴ N/C.
