DeRobijazmisellyg
contestada

A motorcycle being driven on a dirt path hits a
rock. Its 60.-kilogram cyclist is projected over
the handlebars at 20. meters per second into a
haystack. If the cyclist is brought to rest in
0.50 second, the magnitude of the average force
exerted on the cyclist by the haystack is
(1) 6.0 × 10^1 N (3) 1.2 × 10^3 N
(2) 5.9 × 10^2 N (4) 2.4 × 10^3 N

Respuesta :

TaylorBayley
Impulse = mass * change in velocity (change in momentum) = Force * change in time

So, F=(m*change in v)/(change in t)
F=(60*20)/0.5=2400N

Therefore the magnitude of the average force exerted on the cyclist by the haystack is 2.4*10^3N
asuwafohjames

The magnitude of the average force is 2.4×10³ N and The right option is (4) 2.4×10³ N.

To calculate the magnitude of the average force, we use the formula below.

⇒ Formula:

  • F = m(v-u)/t.................. Equation 1

⇒ Where:

  • F = Average force
  • m = mass of the cyclist
  • v = Final velocity
  • u = Initial velocity
  • t = time.

From the question,

⇒ Given:

  • m = 60 kg
  • v = 0 m/s (brought to rest)
  • u = 20 m/s
  • t = 0.50 s

⇒ Substitute these values into equation 1

  • F = 60(0-20)/0.5
  • F = -2400 N
  • F = -2.4×10³ N

Note: the negative sign tells that the force act against the motion of the cyclist.

Hence, the right option is (4) 2.4×10³ N

Learn more about Force here: https://brainly.com/question/13370981

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