Respuesta :

Evaluate for n=5 52+(2)(5)+1 52+(2)(5)+1 =36

Answer: The value of [tex]N^2+2N+1[/tex] for [tex]N=5[/tex] is 36.

Step-by-step explanation:

The given function is [tex]N^2+2N+1[/tex]

To evaluate the value of [tex]N^2+2N+1[/tex] for [tex]N=5[/tex], we need to substitute the value of N=5 we get

[tex](5)^2+2(5)+1\\\\=25+10+1\\\\=36[/tex]

Therefore, the value of [tex]N^2+2N+1[/tex] for [tex]N=5[/tex] is 36.