Respuesta :



Express the system in standard form:
{3 x + 5 y = 13/2 | (equation 1)
{5 x + y = 57/10 | (equation 2)

Swap equation 1 with equation 2:
{5 x + y = 57/10 | (equation 1)
{3 x + 5 y = 13/2 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:
{5 x + y = 57/10 | (equation 1)
{0 x+(22 y)/5 = 77/25 | (equation 2)

Multiply equation 1 by 10:
{50 x + 10 y = 57 | (equation 1)
{0 x+(22 y)/5 = 77/25 | (equation 2)

Multiply equation 2 by 25/11:
{50 x + 10 y = 57 | (equation 1)
{0 x+10 y = 7 | (equation 2)

Divide equation 2 by 10:
{50 x + 10 y = 57 | (equation 1)
{0 x+y = 7/10 | (equation 2)

Subtract 10 × (equation 2) from equation 1:
{50 x+0 y = 50 | (equation 1)
{0 x+y = 7/10 | (equation 2)

Divide equation 1 by 50:
{x+0 y = 1 | (equation 1)
{0 x+y = 7/10 | (equation 2)
Collect results:
Answer:  {x = 1
                {y = 7/10