Respuesta :
Assume interest is compounded at the end of each year, with a principal P over n years at interest i=0.01.
Future value =5300
Then
Future value
= P(1+i)^n
=>
5300=5000((1.01)^n)
Solve for n
1.01^n=5300/5000=1.06
n=1.06^(1/6)=5.856 years.
If interest rate is 1% simple interest, then
n=(1.06-1)/.01=6 years.
Future value =5300
Then
Future value
= P(1+i)^n
=>
5300=5000((1.01)^n)
Solve for n
1.01^n=5300/5000=1.06
n=1.06^(1/6)=5.856 years.
If interest rate is 1% simple interest, then
n=(1.06-1)/.01=6 years.
Answer:
If interest is calculated yearly, it will take Time approximately 6 years
Step-by-step explanation:
For interest compounded continuously we use this formula
A = [tex]pe^{rt}[/tex]
Where A = Amount in future ($5,300)
P = Principal amount ($5,000)
r = interest rate (1% or 0.01)
t = time
Now we put the values
5300 = 5000e[tex]^{(0.01)t}[/tex]
1.06 = [tex]e^{(0.01)t}[/tex]
㏑1.06 = 0.01t
t = ㏑(2) ÷ 0.01
t = 5.82 years rounded to 6 years
If interest is calculated yearly (simple interest)
n = ( 1.06-1 ) / 0.01 = 6 years.
If interest is calculated yearly, it will take Time approximately 6 years.