GeF3H is formed from GeH4 and GeF4 in the combination reaction: GeH4 + 3GeF4 -> 4GeF3H. If the reactiln yield is 92.6%, how many moles of GeF4 are needed to produce 8 mol of GeF3H?

Answer is: 6,48 mol of GeF₄ are needed.
Chemical reaction: GeH₄ + 3GeF₄ → 4GeF₃H.
n(GeF₃H) = 8 mol.
n(GeF₄) = ?
from chemical reaction: n(GeF₃H) : n(GeF₄) = 4 : 3.
8 mol : n(GeF₄) = 4 : 3.
4n(GeF₄) = 24 mol.
n(GeF₄) = 6 mol ÷ 0,926.
n(GeF₄) = 6,48 mol.

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Alleei Alleei · Answer 2 · 2020-04-21T07:08:19+02:00

Answer : The number of moles of [tex]GeF_4[/tex] needed to produce 8 mole of [tex]GeF_3H[/tex] are, 6.48 moles.

Explanation :

The given balanced chemical reaction is:

[tex]GeH_4+3GeF_4\rightarrow 4GeF_3H[/tex]

First we have to calculate the moles of [tex]GeF_4[/tex]

From the balanced chemical reaction we conclude that,

As, 4 moles of [tex]GeF_3H[/tex] produced from 3 mole of [tex]GeF_4[/tex]

So, 8 moles of [tex]GeF_3H[/tex] produced from [tex]\frac{8}{4}\times 3=6[/tex] mole of [tex]GeF_4[/tex]

Now we have to calculate the moles of [tex]GeF_4[/tex] when the reaction yield is 92.6 %.

As, 92.6 % yield produced from 6 moles of [tex]GeF_4[/tex]

So, 100 % yield produced from [tex]\frac{100\%}{92.6\%}\times 6=6.48[/tex] moles of [tex]GeF_4[/tex]

Therefore, the number of moles of [tex]GeF_4[/tex] needed to produce 8 mole of [tex]GeF_3H[/tex] are, 6.48 moles.