Answer:
His acceleration is [tex]49.05\frac{m}{s^{2}}[/tex]
Explanation:
We know that the test pilot is flying with an acceleration equal to 5g
The letter ''g'' is representing the value of the gravity acceleration on Earth.
This value ''g'' is equal to [tex]9.81\frac{m}{s^{2}}[/tex]
In order to find the acceleration of the test pilot we need to multiply the value of ''g'' by 5 ⇒
[tex]5g=(5).(9.81\frac{m}{s^{2}})=49.05\frac{m}{s^{2}}[/tex]
