Now, find the equation for a line that passes through the two points (−1,3) and (4,−5). express your answer in terms of x. the "y=" has been given for you

Respuesta :

The slope of this line is
         
         -5 - 3           -8
m = ----------- = ----------
          4-(-1)           5

Then use the point-slope format to find the equation of this line.

y-3 = (-8/5)(x-(-1)), or   y - 3 = (-8/5)( x + 1)     (answer)

This could be re-written in other forms, such as the slope-intercept form.


The equation of the line passing through the given points needs to be expressed in terms of [tex]x[/tex].

The required equation is [tex]x=-\dfrac{5}{8}y+\dfrac{7}{8}[/tex]

The given points are

[tex](-1,3)[/tex]

[tex](4,-5)[/tex]

The equation of the line is

[tex]y-3=\dfrac{-5-3}{4+1}(x+1)\\\Rightarrow y-3=-\dfrac{8}{5}(x+1)\\\Rightarrow -\dfrac{5}{8}(y-3)=x+1\\\Rightarrow x=-\dfrac{5}{8}y+\dfrac{15}{8}-1\\\Rightarrow x=-\dfrac{5}{8}y+\dfrac{7}{8}[/tex]

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