Answer: D. [tex]4\sqrt{3}[/tex]
Step-by-step explanation:
The given radicals : [tex]\sqrt{3}\times\sqrt{16}[/tex]
According to the property of radicals :
[tex]\sqrt[n]{x^n}=x[/tex]
Therefore, [tex]\sqrt{3}\times\sqrt{16}=\sqrt{3}\times\sqrt{4^2}[/tex]
[tex]=\sqrt{3}\times4\\\\=4\sqrt{3}[/tex]
Therefore, [tex]\sqrt{3}\times\sqrt{16}=4\sqrt{3}[/tex]
Thus, D is the right answer.
