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A line with a slope of -2 crosses the y-axis at (0, 3). The equation of the line is _______

a) -3x + y = 3
b) 3x + y = 2
c) 2x + y = 3
d) 2x + y = 2

Respuesta :

in y = mx + b form, the slope is in the m position and the y int is in the b position
u have a slope of -2 and a y int of 3

so ur equation is : y = -2x + 3...but we need it in standard form

y = -2x + 3.....add 2x to both sides
2x + y = 3 <== ur equation
The point (0,3)  is the y intercept of the line. y - intercelt is at y=3.

So we can use the slope intercept form of the straight line y = mx + b:-

y = -2x + 3

or 
2x + y = 3


Its c).