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A rubber block weighing 60. newtons is resting on a horizontal surface of dry asphalt. what is magnitude of the minimum force needed to start the rubber block moving across the dry asphalt?

Respuesta :

carlosego
First you must look for the coefficient of friction of the dry asphalt. For this case, searching in google, the value is 0.85. Then, you must find the normal force by making a free-body diagram. In the diagram, you sum up forces in vertical direction and find that the normal force is 60N. Then, by sum of forces in a horizontal direction, the friction force will be given by:F = (60) * (0.85) = 51N.51N is the magnitude of the minimum force needed to start the rubber block moving across the dry asphalt
snehashish65

The magnitude of the minimum force needed to start the rubber block moving across the dry asphalt is 51 N.

Given data:

The weight of block is, [tex]W = 60 \;\rm N[/tex].

The block will start moving when it overcomes the frictional force between the asphalt surface and the block. Therefore,

[tex]f = \mu \times N[/tex]

here, [tex]\mu[/tex] is the coefficient of friction of Asphalt, and its value is 0.85.

N is the normal reaction force which is equal to weight of block.

Solving as,

[tex]f = 0.85 \times 60\\f =51 \;\rm N[/tex]

Thus, the magnitude of the minimum force needed to start the rubber block moving across the dry asphalt is 51 N.

Learn more about the frictional force here:

https://brainly.com/question/23575742?referrer=searchResults

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