Respuesta :
(78.92) (50.69)+(80.92)(.4931)
(4000)+(39.90)
=79.9 amu
Answer is 79.9 amu
It will help you
(4000)+(39.90)
=79.9 amu
Answer is 79.9 amu
It will help you
The atomic mass of bromine has been 79.9365 amu.
The atomic mass from the isotopes can be calculated as :
Average atomic mass = (atomic mass of 1 isotope [tex]\times[/tex] % abundance) + (atomic mass of 2nd isotope [tex]\times[/tex] % abundance)
Given,
atomic mass of 1 isotope = 78.98 amu
% abundance of 1 isotope = 50.69% = [tex]\rm \dfrac{50.69}{100}[/tex]
% abundance of 1 isotope = 0.5069
Atomic mass of 2nd isotope = 80.92 amu
% abundance of 2nd isotope = 49.31% = [tex]\rm \dfrac{49.31}{100}[/tex]
% abundance of 2nd isotope = 0.4931
Average atomic mass of bromine = (78.98 amu [tex]\times[/tex] 0.5069) + (80.92 amu [tex]\times[/tex] 0.4931)
Average atomic mass of bromine = 40.0349 + 39.9016
Average atomic mass of bromine = 79.9365 amu
Atomic mass of bromine has been 79.9365 amu.
For more information about the atomic mass, refer to the link:
https://brainly.com/question/1853460