Answer is: XeF₄.
p₁ (F₂) = 8,0 atm.
p₁ (Xe) = 1,7 atm.
p₂ (F₂) = 4,6 atm.
p₂ (Xe) = 0 atm, all reacted.
p - partial pressure.
pressure of F₂ reacted = Δp (F₂) = 8.0 - 4.6 = 3.4 atm.
pressure of Xe reacted = Δp(Xe) = 1,7 - 0 = 1,7 atm.
Δp (F₂) / Δp(Xe) = 3,4 atm / 1,7 atm = 2:1.
Reaction: 2F₂ + Xe → XeF₄ (xenon-tetrafluoride)