(HELP PLEASE) if f(x)=x/3-2 and g(x)=3x^2+2x-6 , find (f+g)(x)

Answer:
(A)
Step-by-step explanation:
The given functions are:
[tex]f(x)=\frac{x}{3}-2[/tex] and [tex]g(x)=3x^2+2x-6[/tex]
Now, [tex](f+g)(x)=f(x)+g(x)[/tex]
therefore, [tex](f+g)(x)=\frac{x}{3}-2+3x^2+2x-6[/tex]
=[tex]3x^2+2x+\frac{x}{3}-8[/tex]
=[tex]\frac{9x^2+6x+x-24}{3}[/tex]
=[tex]\frac{9x^2+7x-24}{3}[/tex]
=[tex]3x^2+\frac{7}{3}x-8[/tex]
Thus, [tex](f+g)(x)=3x^2+\frac{7}{3}x-8[/tex]
Hence, Option A is correct.