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If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude of the force of friction?

A.310 N
B.0 N
C.620 N

If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N what is the magnitude of the force of friction A310 N B0 class=

Respuesta :

Answer:

[tex]f_k = 310N[/tex]

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F -[tex]f_k[/tex] = 0

where F is the force applied and [tex]f_k[/tex] is the friction force. Replacing the value of F, we get:

310N -[tex]f_k[/tex] = 0

Finally, solving for [tex]f_k[/tex]:

[tex]f_k = 310N[/tex]

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