crazyasi0105
crazyasi0105
29-11-2017
Mathematics
contestada
1/4(40-8x)=19x+2-5x
1/4(40-8x)=19x+2-5x
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tynollette
tynollette
29-11-2017
[tex] \frac{1}{4}*40- \frac{1}{4}*8x=19x-5x+2 [/tex]
10-2x=14x+2
Add 2x on both sides: 10=16x+2
subtract 2 on both sides: 8=16x
divide by 16 on both sides: x=8/16=[tex] \frac{1}{2} [/tex]
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