Respuesta :
it is c2h5 if you our doing it on edunitey thats all i can say
Answer : The empirical formula is, [tex]C_2H_5[/tex]
Solution : Given,
Mass of C = 20.75 g
Mass of H = 4.25 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Step 1 : convert given masses into moles.
Moles of C = [tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{20.75g}{12g/mole}=1.73moles[/tex]
Moles of H = [tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.25g}{1g/mole}=4.25moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.73}{1.73}=1[/tex]
For H = [tex]\frac{4.25}{1.73}=2.5[/tex]
The ratio of C : H = 1 : 2.5
In the whole number the ratio of C : H = 2 : 5
The mole ratio of the element is represented by subscripts in empirical formula.
Therefore, the empirical formula is, [tex]C_2H_5[/tex]
