Respuesta :

altavistard
This expression is the difference of two cubes:

x^3     y^3
----- - -------
2^3     3^3

The rule here is  a^3 - b^3 = (a - b)(a^2 + ab + b^2), so


x^3     y^3                          x^2       x^3y^3        y^2
----- - ------- = (x/2 - y/3)*(-------- + ----------- + --------- )
2^3     3^3                          2^2          6^3          3^2

Answer:

(1)/(8)x^(3)+(1)/(27)y^(3)

Step-by-step explanation:

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