HELP
In ΔSTU, SU = 18 and TU = 13. Find m∠T to the nearest tenth of a degree.

Answer:
Measure of ∠T = 54.2°
Step-by-step explanation:
In the given triangle STU, SU = 18 and TU = 13.
We have to find the measure of angle T.
Since tanT = [tex]\frac{Height}{Base}[/tex]
tanT = [tex]\frac{SU}{TU}[/tex]
tanT = [tex]\frac{18}{13}[/tex]
∠T = [tex]tan^{-1}(1.3846)[/tex]
∠T = 54.16 ≈ 54.2°