Iron(111) chloride, fec13 , can be made by the reaction of iron with chlorine gas. how much iron, in grams, will be needed to completely react with 58.0 g of c12
The balanced chemical equation that describes this reaction is: 2Fe + 3Cl2 ............> 2FeCl3
Using the periodic table: molar mass of iron III = 55.845 grams molar mass of chlorine = 2*35.453 = 70.906 grams
From the balanced equation above, 2 moles of iron are required to react with 3 moles of chlorine. This means that: 2*55.845 = 111.69 grams with iron are required to react with 3*70.906 = 212.718 grams of chlorine. To know the amount of iron needed to react with 58 grams of chlorine, we will simply use cross multiplication as follows: mass of iron = (58*111.69) / (212.718) = 30.45355 grams
