Respuesta :

W0lf93
We know that the atmospheric co2 in 1850 was 280 parts per million. Thus we have that the percentage is 280/1 million * 10000 . Thus we have that the percent of atmospheric co2 in 1850 was 2.8%

Answer: 0.028

Step-by-step explanation:

ppm is defined as the mass of the solute present in one million [tex]10^6[/tex] parts by mass of the solution.

percent is defined  the the mass of the solute present in hundred parts by mass of the solution.

[tex]ppm=\frac{\text {mass of solute}}{\text {mass of solution}}\times 10^6[/tex]

Given: Atmospheric [tex]CO_2[/tex] = 280 ppm

[tex]10^6[/tex] parts contain 280 parts

100 parts will contain =[tex]\frac{280}{10^6}\times 100[/tex] = 0.028

Thus the percent of atmospheric [tex]CO_2[/tex] is 0.028.

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