Respuesta :
Use a punnet square!
Knuckles Tongue
H= dominant R= dominant
h= recessive r= recessive
H h R r
___________ ____________
H- HH Hh R RR Rr
___________ ____________
h- Hh hh r Rr rr
ratios are set up like this:
# : # : #
homo-dom : hetero : homo-rec
so for these traits the ratio would be..
Knuckles-- 1 : 2: 1
Tongue-- 1 : 2 : 1
If you still don't understand PM me and i'll be happy to explain alleles and such (:
Knuckles Tongue
H= dominant R= dominant
h= recessive r= recessive
H h R r
___________ ____________
H- HH Hh R RR Rr
___________ ____________
h- Hh hh r Rr rr
ratios are set up like this:
# : # : #
homo-dom : hetero : homo-rec
so for these traits the ratio would be..
Knuckles-- 1 : 2: 1
Tongue-- 1 : 2 : 1
If you still don't understand PM me and i'll be happy to explain alleles and such (:
Answer:
9 tongue roller and smooth middle knuckles: 3 tongue roller and hairy middle knuckles : 3 Non-roller and smooth middle knuckle: 1 non-roller and hairy middle knuckle.
Explanation:
Let's assume that allele for tongue roll is "R" and the allele for the non-roller phenotype is "r". Similarly, allele "S" determines smooth middle knuckles while its recessive counterpart "s" gives hairy middle knuckles.
The genotype of heterozygous parents would be "RrSs" and a cross between two "RrSs" genotypes would give progeny in the following phenotype ratio=
9 tongue roller and smooth middle knuckles: 3 tongue roller and hairy middle knuckles : 3 Non-roller and smooth middle knuckle: 1 non-roller and hairy middle knuckle.
