Answer: Our numbers are: [tex]\sqrt{8/3}[/tex], π, 3.01245 and [tex]\sqrt{17}[/tex]. Let's analyze them:
1) [tex]\sqrt{8/3}= \sqrt{16/6} =4/\sqrt{6}[/tex] and [tex]\sqrt{6} \geq\sqrt{4}= 2[/tex], so [tex]4/\sqrt{6} \leq4/2 = 2[/tex]
So [tex]\sqrt{8/3}\leq2[/tex]
2) the number pi is 3.14159265
3) this number is 3.01245, doesn't require more analyzing-
4) [tex]\sqrt{17}[/tex], we know that [tex]\sqrt{16} = 4[/tex], then [tex]\sqrt{17} \geq 4[/tex]
So the correct order from greatest to lowest is:
[tex]\sqrt{17}[/tex], π , 3.01245, [tex]\sqrt{8/3}[/tex]
You also can check it with a calculator, but it isn't the idea of the problem.
