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City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?

Your answer:


City A was 5° C, and City B was 4° C.

City A was 3° C, and City B was −1° C.

City A was 8° C, and City B was −3° C.

City A was 5° C, and City B was −5° C.

Respuesta :

musiclover10045

City A = x

City B = y

1st equation: 4x-8 =3y

 2nd equation: x-2y = -3 , rewrite as x = 2y-3

replace x in eq. 1 with equation 2

4(2y-3) -8 =3y

8y-12-8=3y

8y-20 = 3y

-20 = -5y

y = -20/-5 = 4

x = 2y-3 = 2(4)-3 = 5

City A was 5° C, and City B was 4° C. 


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