Answer:
Equation:
N2(g) + 3H2(g) → 2NH3(g)
Check for limiting reactant
Molar mass N2 = 28g/mol
mol N2 in 31,500g = 31,500/28 = 1,125 mol N2
This will require 1,125*3 = 3,375 mol H2
Molar mass H2 = 2g/mol
Mol H2 in 5,220g = 5,220/2 = 2,610 mol H2
The H2 is limiting
From the equation:
3 mol H2 will produce 2mol NH3
2610 mol H2 will produce 2610*2/3 = 1,740 mol NH3
Molar mass NH3 = 17g/mol
Mass of 1740 mol NH3 = 1740*17 = 29,580g NH3 produced
Mass of NH3 produced = 29.6kg
