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Suppose a problem has vertex (5 -3) and also passes through the point (6,1) write the equation of the parabola in vertex form.
A) y= (x-5)^2-3
B) y= 4(x-5)^2-3
C) y=4(x+5)^2-3
D) y=4(x-5)^2+3

Respuesta :

In vertex form it s 
y = a(x - 5)^2 - 3       because  the vertex is at (5,-3)  .  a is a constant to be found.
Plugging in the point (6,1) we get

1 = a(6-5)^2 - 3
1 = a - 3
a = 4

answer is y = 4(x - 5)^2 - 3

Its B


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