[tex]I=\frac{k}{r}[/tex], where [tex]k[/tex] is constant of variation.
[tex]\frac{2}{1} = \frac{k}{960}
\\k=2\cdot960=1920[/tex].
Since we know the data to find the current when the resistance is 480 Ohms [tex]\Rightarrow[/tex] [tex]I=\frac{k}{r}=\frac{1920}{480}=4 \ amperes[/tex].
