Respuesta :
Because the three numbers are consecutive, if the first one is x, the second should be x+1, and the third one is x+2
the three numbers add up to be 5982, so
x+(x+1)+(x+2)=5982
3x+3=5982
3x=5979
x=1993
1993,1994,1995
the three numbers add up to be 5982, so
x+(x+1)+(x+2)=5982
3x+3=5982
3x=5979
x=1993
1993,1994,1995
Answer:
The birth years of first person is 1993.
The birth years of second person is 1994.
The birth years of third person is 1995.
Step-by-step explanation:
Three friends were born in consecutive years
Let the birth years of first person be x,
Let the birth years of second person be (x+1)
Let the birth years of third person be(x+2)
The sum of their birth years is 5982.
[tex]x+(x+1)=(x+2)=5982[/tex]
Solving the given equation for x:
[tex]3x+3=5982[/tex]
[tex]x=\frac{5982-3}{3}=1993[/tex]
The birth years of first person = x = 1993
The birth years of second person = (x+1) = 1993+ 1 = 1994
The birth years of third person = (x+2) = 1993+2 = 1995
