Refer to the diagram shown below.
m = 300 kg, the mass of the rollercoaster
θ = 60°
g = 9.8 m/s²
Friction is ignored.
The component of the weight acting down the incline (no friction) is
F = mg sinθ
= (300 kg)*(9.8 m/s²)*sin(65°)
= 2664.5 N
If the acceleration down the incline, then
(300 kg)*(a m/s²) = 2664.5 N
a = 2664.5/300 = 8.882 m/s²
Answers:
(1) F = 2664.5 N acting down the hill
(2) a = 8.882 m/s²
