so, we know that, in 1oz of baked potato, there are 48.3 calories, ok..how many calories in 3 and 1/3 oz then?
now, bear in mind, we first convert the mixed fraction to "improper", and then use that,
[tex]\bf \begin{array}{ccll}
\stackrel{\stackrel{baked}{potato}}{oz}&calories\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&48.3\\
3\frac{1}{3}&p
\end{array}\implies \cfrac{1}{3\frac{1}{3}}=\cfrac{48.3}{p}\implies \cfrac{\frac{1}{1}}{\frac{3\cdot 3+1}{3}}=\cfrac{48.3}{p}[/tex]
[tex]\bf \cfrac{\frac{1}{1}}{\frac{10}{3}}=\cfrac{48.3}{p}\implies \cfrac{1}{1}\cdot \cfrac{3}{10}=\cfrac{48.3}{p}\implies \cfrac{3}{10}=\cfrac{48.3}{p}
\\\\\\
3p=483\implies p=\cfrac{483}{3}\implies \boxed{p=\stackrel{calories}{161}}[/tex]
now, we know that in 1oz of chicken gas 24.6 calories, so, how many calories then in 5 and 1/4 oz?
[tex]\bf \begin{array}{ccll}
\stackrel{chicken}{oz}&calories\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&24.6\\
5\frac{1}{4}&c
\end{array}\implies \cfrac{1}{5\frac{1}{4}}=\cfrac{24.6}{c}\implies \cfrac{\frac{1}{1}}{\frac{5\cdot 4+1}{4}}=\cfrac{24.6}{c}[/tex]
[tex]\bf \cfrac{\frac{1}{1}}{\frac{21}{4}}=\cfrac{24.6}{c}\implies \cfrac{1}{1}\cdot \cfrac{4}{21}=\cfrac{24.6}{c}\implies \cfrac{4}{21}=\cfrac{24.6}{c}
\\\\\\
4c=516.6\implies c=\cfrac{516.6}{4}\implies \boxed{c=\stackrel{calories}{129.15}}[/tex]
so, how many calories in that meal? well, p + c.
