Answer: D . [tex]((y+2)=-2(x-5)[/tex]
Step-by-step explanation:
The equation of a line passing through two points (a,b) and (c,d) in point-slope form is given by :-
[tex](y-d)=\dfrac{d-b}{c-a}(x-c)[/tex]
From the given graph ,it can be seen that the line is passing through two points A(1,6) and B(5,-2).
Then the equation for the line AB in point-slope form would be :-
[tex](y-(-2))=\dfrac{-2-6}{5-1}(x-5)[/tex]
[tex]\Rightarrow\ (y+2)=\dfrac{-8}{4}(x-5)[/tex]
[tex]\Rightarrow\ (y+2)=-2(x-5)[/tex]
Hence, the equation is a point slope form equation for line AB :
[tex](y+2)=-2(x-5)[/tex]