From Beer-Lambert's law' A = ECl Since the slope is 1550.7
thus A = 1550.7* 0.000529 M = 0.8203203 Since A = Log (Io/I) and T% = I/Io * 100% Io/I = AntiLog(A) and hence T% = { 1/ AntiLog (A) } *100%
T%={1/AntiLog 0.8203203)*100% T%=0.8601654108*100% T%= .860