Triangle ABC is translated to image A′B′C′. In this translation, A(5, 1) maps to A′(6, –2). The coordinates of B′ are (–1, 0). The coordinates of B are (-2, 3). How?

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Answer:

B (-2, 3)

Step-by-step explanation:

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In geometry, translation is the movement of a point or shape from one position to another.

The translation from [tex]\triangle ABC[/tex] to [tex]\triangle A'B'C'[/tex] is [tex](x,y) \to (x + 1, x - 3)[/tex]

Given that:

[tex]A = (5,1) \to A' = (6,-2)[/tex]

[tex]B = (-2,3) \to B' = (-1,0)[/tex]

The transformation is calculated as follows:

[tex](x,y) = (x + a, x + b)[/tex]

Using A and A', we have:

[tex](6,-2) = (5 + a, 1 + b)[/tex]

By comparison:

[tex]5 + a = 6[/tex]     and    [tex]-2 = 1 + b[/tex]

So, we have:

[tex]5 + a = 6[/tex]

[tex]a = 6 - 5[/tex]

[tex]a = 1[/tex]

[tex]-2 = 1 + b[/tex]

[tex]b =-2 - 1[/tex]

[tex]b = -3[/tex]

Recall that:

[tex](x,y) = (x + a, x + b)[/tex]

So, we have:

[tex](x,y) = (x + 1, x - 3)[/tex]

Hence, the translation of the triangle is:

[tex](x,y) \to (x + 1, x - 3)[/tex]

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