For this case, what we must do is find the dimensions of the patio.
For this, we use the following perimeter equation:
[tex] p = 2w + 2l
[/tex]
Where,
w: width of the patio
l: length of the patio
Substituting values we have:
[tex] 2w + 2l = 134
[/tex]
Then, on the other hand, we know that:
The patio is 5 feet less wide than it is long:
[tex] w = l-5
[/tex]
We then have the following equations:
[tex] 2w + 2l = 134
w = l-5
[/tex]
Solving by substitution we have:
[tex] 2 (l-5) + 2l = 134
2l -10 + 2l = 134
2l + 2l = 134 + 10
4l = 144
[/tex]
[tex] l = \frac{144}{4}
l = 36
[/tex]
Then, the width is:
[tex] w = l-5
w = 36-5
w = 31
[/tex]
Answer:
The dimensions of the patio are given by:
[tex] l = 36 feet
w = 31 feet [/tex]
