Answer:
The value of (g ∘ f)(-2) is 1
Step-by-step explanation:
Given two functions
[tex]f(x)=x^2, g(x)=x-3[/tex]
we have to evaluate (g ∘ f)(-2).
As, (g ∘ f)(-2)=g(f(x))
[tex]g(f(x))=g(x^2)[/tex]
As g(x)=x-3
[tex]g(x^2)=x^2-3[/tex]
Therefore,
[tex](g o f)(x)=x^2-3[/tex]
To find the value of (g ∘ f)(-2), we have to substitute x=-2
[tex](g o f)(-2)=(-2)^2-3=4-3=1[/tex]
Hence, the value of (g ∘ f)(-2) is 1
