Respuesta :

The answer to this question would be: 0.050 m

In this question, you have a 0.025m concentration of K2CO3 or potassium carbonate solution. The compound will dissociate into 2 K+ and 1 (CO3)2-

Then the amount of K+ ion in this solution assuming complete dissociation should be: 2/1 * 0.025m= 0.050m

The complete dissolution of 0.025 M [tex]\rm K_2CO_3[/tex] will result in 0.050 M [tex]\rm K^+[/tex].

The complete dissolution of [tex]\rm K_2CO_3[/tex] will result in:

[tex]\rm K_2CO_3\;\rightarrow\;2\;K^+\;+\;CO_3^2^-[/tex]

1 molecule of [tex]\rm K_2CO_3[/tex] will gives 2 molecules of [tex]\rm K^+[/tex].

So 0.025 M [tex]\rm K_2CO_3[/tex] will give: 1 M

0.025 M [tex]\rm K_2CO_3[/tex] = [tex]\rm 0.025\;\times\;2\;K^+[/tex] M

= 0.05 M [tex]\rm K^+[/tex].

Thus the complete dissolution of 0.025 M [tex]\rm K_2CO_3[/tex] will result in 0.050 M [tex]\rm K^+[/tex]

For more information, refer to the link:

https://brainly.com/question/788696